Find all the zeroes of the polynomial 3x⁴+6x³-2x²-10x-5 if two of its zeroes are (√5/3) and (-√5/3)
(class 10 CBSE SAMPLE PAPER 2017-18 MATHS)
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Method of finding the remaining zeros of a polynomial when sum of its zeros are given:
We firstly write the factor of polynomial using given zeros and multiply them to get g(x). Then divide a given polynomial by g(x).
The quotient so obtained give other zeros of given polynomial and we factorise it to get other zeros.
SOLUTION:
Given :
Two zeroes are (√5/3) & (-√5/3)
So, (x-√5/3) & (x+√5/3) are the factors of given Polynomial.
(x-√5/3) (x+√5/3)
= x²- 5/3= (3x²-5)/3
= (3x²-5)/3=0
3x²-5 is a factor of given Polynomial
Divide 3x⁴+6x³-2x²-10x-5 by 3x²-5
[Division is in the attachment.]
Hence , all the zeroes of the given Polynomial are:
(√5/3), (-√5/3), -1,1
Hope this will help you...
We firstly write the factor of polynomial using given zeros and multiply them to get g(x). Then divide a given polynomial by g(x).
The quotient so obtained give other zeros of given polynomial and we factorise it to get other zeros.
SOLUTION:
Given :
Two zeroes are (√5/3) & (-√5/3)
So, (x-√5/3) & (x+√5/3) are the factors of given Polynomial.
(x-√5/3) (x+√5/3)
= x²- 5/3= (3x²-5)/3
= (3x²-5)/3=0
3x²-5 is a factor of given Polynomial
Divide 3x⁴+6x³-2x²-10x-5 by 3x²-5
[Division is in the attachment.]
Hence , all the zeroes of the given Polynomial are:
(√5/3), (-√5/3), -1,1
Hope this will help you...
Attachments:
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