Question

find all the zeros of x⁴-6x³+6x²+6x-7 its two factor are 3+✓2,3-✓​

Answer 1

-√1,√1

Step-by-step explanation:

let p(x)=x^4-6x^3+6x^2+6x-7

and 3+√2,3-√2are zeroes of p(x)

p(x)=x-3-√2),(x-3+√2)

x^2-6x+7

now,

divide p(x) by x^2-6x+7

=x^2-1

on factorising x^2-1 ans will be

(x-√1),(x+√1)

x=√1,x=-√1