Question

Find all zeroes of
p(y)=y^3-2y^2+y+4​

Answer 1

Answer:

Step-by-step explanation:

y^3-2y^2+y+4​

using hit and trial method

always start with -1, +1

y = -1

(-1)³ - 2×(-1)² + (-1) + 4

-1 -2 -1 +4 = 0

it means y+1 divides the equation with remainder 0

on dividing we get

(y+1)(y²-3y+4)

y²-3y+4

y = (3±√-7)/2

y = (3±i√7)/2 , -1