Math, asked by akshatgairola, 9 months ago

Find all zeroes of the polynomial p(x)= 3x³+10x²-9x-4, if one zerof it zero is 1

Answers

Answered by 23adaul
1

Answer:

3x3-10x2+9x-2=0

Three solutions were found :

x = 2

x = 1/3 = 0.333

x = 1

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  1 more similar replacement(s).

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (((3 • (x3)) -  (2•5x2)) +  9x) -  2  = 0

Step  2  :

Equation at the end of step  2  :

 ((3x3 -  (2•5x2)) +  9x) -  2  = 0

Step  3  :

Checking for a perfect cube :

3.1    3x3-10x2+9x-2  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  3x3-10x2+9x-2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  9x-2

Group 2:  3x3-10x2

Pull out from each group separately :

Group 1:   (9x-2) • (1)

Group 2:   (3x-10) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Step-by-step explanation:

Answered by Anonymous
1

Refer to the attatched file.

:)

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