Question

find area of quadrant of a circle whose circumference is 22cm​

Answer 1

Answer:

$Area \: of \: quadrant = \frac{1}{4} \times area \: of \: circle \\ = \frac{1}{4} \times (\pi \: r ^{2} )$

$It \: is \: given \: that \\ </p><p> Circumference = \: 2\pi \: r \\ 22 = 2\pi \: r \\ \frac{22}{2} = \pi \: r \\ 11 = \pi \: r \\ \frac{11}{\pi} = r \\ r = \frac{11}{\pi } \\ r = \frac{11}{ \frac{22}{7} } \\ r = 11 \times \frac{7}{22} \\ r = \frac{7}{2} cm$

$Now \: area \: of \: quadrant = \frac{1}{4} \times area \: of \: circle \\ = \frac{1}{4} (\pi \: r ^{2} ) \\ = \frac{1}{4} \times \frac{22}{7} \times ( \frac{7}{2} ) ^{2} \\ = \frac{1}{4} \times \frac{22}{7} \times \frac{7 \times 7}{2 \times 2} \\ = \frac{1}{2} \times \frac{11}{1} \times \frac{7}{4} \\ \frac{77}{8} \: cm ^{2}$

Hope it helps uhh

Answer 2

Answer:

77/8cm square is the answer for the question

Refer the attachment