Question

the curve satisfying the differential equation dx/dy=x+2yx^2/y-2x^3 and passing through (1,0) is given by​

Answer 1

Answer:

The required answer is $(10/3, 0), (0,0), (5/3, 5/3).$

Step-by-step explanation:

Given: the equation of three side of the triangle.

$y=x, y=0$ and $3x+3y=10$

To find: We have to find vertices of the given triangle.

Solution:

Draw the graph of $y=x, y=0$ and $3x+3y=10$

$3x+3y=10$ coordinates are $(10/3,0),(0, 10/3)$

To determine the location of point c, solve $y=x$ and $3x+3y=10$, we get

$3x+3x=10$

Then, calculate values.

$6x=10, x=5/3$ and $y=5/3$

Hence, the vertices of the triangle is (OAC) is $(10/3, 0), (0,0), (5/3, 5/3).$

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