find area of rectangle whose sides are 47/8m and 62/9m.
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4
area of rectangle=l×b
=47/8×62/9
=40.48m²
Answered by
4
area of rectangle= l×b
so,.
47/8 ×62/9
=5.875 × 6.888
= 40.467m^2
=40.48m^2
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