the amplitude a of damped oscillator becomes half in 5 mins. the amplitude after 10 minutes will be
Answers
Answer:
Explanation:
Amplitude of damped oscillator A=A0e−λt; λ =constant, t = time For t =1 min. A02=A0e−λt⇒eλ=2 For t = 3 min. A=A0e−λ×3=A0(eλ)3=A023
the amplitude a of damped oscillator becomes half in 5 mins. the amplitude after 10 minutes will be one-fourth
Explanation:
Let the amplitude be A
Since the amplitude becomes half in 5 minutes
Therefore, after 5 minutes, the amplitude = A/2
In the next 5 minutes, the amplitude will be half of this value
Thus, the amplitude after 10 minutes = A/2² = A/4
Thus, the amplitude after 10 minutes will be 1/4 of the original amplitude.
Hope this answer is helpful.
Know More:
Q: The amplitude of damped oscillator becomes 1/3 in 2sec its amplitude after 6sec is 1/n times the original the value of n is:
Click Here: https://brainly.in/question/13386965
Q: Q: The amplitude of a damped oscillator decreased to 0.9 times to its original magnitude in 5s .In another 10s it will decrease to alpha times its original magnitude,where alpha equals to:
Click Here: brainly.in/question/87223