Question

Find area of the general quadrilateral whose diagonal

is 20 cm long and lengths of altitudes from opposite vertices are 12cm and 10cm

with explantion

Answer 1

Answer:

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Answer 2

Explanation : Given ABCD is a quadrilateral with AC = 20cm and BP = 9cm and OD = 15cm and BP perpendicular AC and OD perpendicular AC

area of ∆ABC = 1/2* AC *BP = 1/2 * 20* 9 = 90cmof quadrilateral = area of ∆ADC + ∆ABC = 90 + 150

Area ofsq

[Area of ∆ ABC = 90 cmsq]

(area of ∆ADC ) = 1/2 * AC * OD =1/2 * 20 * 15 =150cm

Area quadrilateral (ABCD)=240

Answer : 240cm

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