Question

Find by construction, the centre of a circle using only a 60-30 Set Square and a Pencil. Also mention which Theorem is used here and mention any limitations.

Answer 1

Answer:

To find the centre of a circle using 60-30 setsquare and a pencil are below:

Step-by-step explanation:

1.At first, draw draw a line using 60-30 set square, on 60° side. let this line cut the circle at A and B.

2.Now draw the line BC using 60-30 set square, on the 30° side. let let c be the point of intersection of the circle.

3.Now join AC.

4.let "O" the midpoint of AC.

5.If "O" is the midpoint of AC then "O" is the midpoint of circle Hope this answer helps you.

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Answer 2

Answer:

Procedure:

1. Draw line using 60-30 set square, on 60 degree side.Let this line cut the circle at A and B.

2. Draw the line BC, using 60-30 set square, on 30 degree side. Let C be the point of intersection of the circle.

3. Join AC

4. Let 'O' be the mid point of AC

Then 'O' is the centre.

• The key point is NOT the 30–60, it is that the other angle is a right angle.

• If you draw a diameter in a circle and then draw two lines from the points where it meets the circumference to another point on the circumference then the angle produced is 90 degrees.

• So you do it in reverse. You put the 90 degree corner of the set square on the circumference of the circle and draw a line using the hypotenuse as a ruler. (It does not matter where the line is drawn.) This creates a diameter. You then do it a second time, moving the setsquare (you can just rotate it), and produce another diameter where the diameters cross is the centre.