find differentiation of function y
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take log both sides , so
log y = sin x^2 log (x)
now differentiating both sides
y dy/dx = 2xcos x^2 * log x + sin x^2 /x
hence dy/dx = y (2xcos x^2 * log x + sin x^2 /x)
dy/dx = x^sin x^2 (2xcos x^2 * log x + sin x^2 /x)
log y = sin x^2 log (x)
now differentiating both sides
y dy/dx = 2xcos x^2 * log x + sin x^2 /x
hence dy/dx = y (2xcos x^2 * log x + sin x^2 /x)
dy/dx = x^sin x^2 (2xcos x^2 * log x + sin x^2 /x)
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