Question

determine the point on the graph of linear equation 2x+3y=15 whose abscissa is7\2times its ordinate

Answer 1

Given equation is 2x+3y=15

$2x + 3y = 15$
$3y = 15 - 2x$
$y = \frac{15 - 2x}{3}$

Now, Given that abscissa is 7/2 times its ordinate

As we know that abscissa = x and ordinate = y
Therefore, Given that
$x = \frac{7}{2} \times y$
Now, Substituting value of y
$x = \frac{7}{2} \times \frac{15 - 2x}{3}$

By solving this equation
we get value of x = 21/4

and substituting the value of this x in equation of y we get y = 3/2

∴ point is [(21/4),(3/2)]

Answer 2

Answer:

I don't know the answer of the question