9x^2-3x^2-5x-1 factorise it
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9x³-3x²-5x-1
using remainder theorem
we see, (x-1) is factor of the expression
using long division method , divide the expression by (x-1)
you will get the quotient as 9x²+6x+1 which is (3x+1)²
so your factors will be (x-1)(3x+1)²
using remainder theorem
we see, (x-1) is factor of the expression
using long division method , divide the expression by (x-1)
you will get the quotient as 9x²+6x+1 which is (3x+1)²
so your factors will be (x-1)(3x+1)²
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