Question

find differentiation of y = 4x⁴ +3x³ + 5/x +9

Answer 1

Answer:

Step-by-step explanation:

1. dy/dx=4(dx^4/dx)+3(dx^3/dx)+5(dx^-1/dx)+0(constant diffrentiation is 0)
2. dy/dx=4(4x^3)+3(3x^2)+5(-1x^-2) (using rule)
3. dy/dx=16x^3+9x^2+-5x^-2(using rule)
4. dy/dx=16(3x^2)+9(2x)-5(-2x^-3)
5. dy/dx=48x^2+18x-10x^-3
6. dy/dx=48(2x)+18-10(-3x^-4)
7. dy/dx=96x+0+30/X^4(CONSTANT DIFFRENCIATION=0)
8. dy/dx=96+30x^-4
9. dy/dx=0+30(-4x^-5)
10. dy/dx=-120x^-5