find discriminant of 4x²+4√3x+3
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discriminant = b^2-4ac
= (4√3)^2-4(4)(3)
=48-48=0
hope it helps
azad26:
i am confused that how 48 comes
Answered by
1
b^2 -4ac
(4root3)^2-4×4×3
48-48 = 0
therefore the discriminant is real and equal
(4root3)^2-4×4×3
48-48 = 0
therefore the discriminant is real and equal
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