Math, asked by Amanpal678, 1 year ago

The strength of school when increased by 9% becomes 32% find the original strength of school​

Answers

Answered by AkshaySonawan
0

Initial Strength Of School (U)=X

Final Strength Of School (V)=32

Increase=9%

Therefore:

Final Strength Of School÷Increase= Initial Strength Of School

Increase=U

Therefore

32÷9= U

32÷5=35

3.5 Rounded Off Is 4

Therefore The Strength Is 4 or 3 Percent

4% Or 3%

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