Question

find Discriminat of 4x^2-8x-3

Answer 1

HI THERE!

$discriminant = {b}^{2} - 4ac$
Here, b=-8,a=4and c=-3
$d = {( - 8)}^{2} - 4 \times 4 \times ( - 3) \\ = 64 + 48 \\ = 112$
Hence the discriminant is 112.

Answer 2

HELLO THERE!

Given equation: 4x² - 8x - 3

Formula of Discriminant is,

$D = b^{2}-4ac$

In the given equation,

a = 4, b = -8, c = -3

So,

$D = (-8)^{2} - 4\times4\times(-3)\\\\= 64 + 48\\\\= 112$

So, your answer is 112, which is greater than zero, but not a perfect square. So, roots will not be integral, but they will be real.

THANKS!