Find dy/dx if x=cos theta and y= sin theta at theta=pi/4
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Given that
x = cosθ, y = sinθ
Differentiate x and y with respect to θ, we get
dx/dθ = -sinθ and dy/dθ = cosθ ...(1)
Now evaluate dy/dx
dy/dx = [(dy/dθ)/(dx/dθ)] { using chain rule ]
⇒ dy/dx = (cosθ)/(-sinθ)
⇒ dy/dx = -cotθ
At θ = π/4,
⇒ dy/dx = -cot(π/4)
⇒ dy/dx = -1
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