Question

Find dy/dx, if y=sin⁻¹ - sin⁻¹√1-x² , 0 < x < 1

Answer 1

Answer:

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y=sin^-1(x)+sin^-1√(1-x^2).

Let sin^-1(x)=A. , then x= sinA

y= A+ sin^-1√(1-sin^2 A)

y= A + sin^-1(cosA).

or. y=A+sin^-1{sin(π/2-A)}.

or. y = A +π/2 -A

or. y= π/2.

So, dy/dx = 0.

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