Question

find dy/dx of y=cos^-1(2x/1+x^2)​

Answer 1

Answer:

Step-by-step explanation:let x be tan theta

y=cos^-1(2tan theta/1+tan^2theta)

y=cos^-1(cos 2theta)

y=2theta

dy/dtheta=2

x=tan theta

Or,Theta=tan^-1x

dx/dtheta=sec^2theta

dy/dx=dy/dtheta×dtheta/dx

dy/dx=2×(1/sec^2theta)

dy/dx=2cos^theta

dy/dx=2cos^2(tan^-1 x)

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