Math, asked by Rudrapratappanda, 1 year ago

find dy/dx=xy2+x2y+1=0

Answers

Answered by boomishadhamodharan

0

ddx(x2y+xy2)=ddx(6)

ddx(x2y)+ddx(xy2)=ddx(6)

[2xy+x2dydx]+[1y2+x2ydydx]=0

2xy+x2dydx+y2+2xydydx=0

x2dydx+2xydydx=−2xy−y2

[x2+2xy]dydx=−2xy−y2

dydx=−2xy−y2x2+2xy

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