Question

Find equation of parabola open left vertex (2,1) and passing through (1,3)

Answer 1

Answer:

The equation of parabola be y+x+k=0

It passes through 2,1

k=−(x+y)=−(2+1)=−3

Solving y+x−3=0 and x=y−1.

We have y=2,x=1

1=

2

a+1

,a=3

2=

2

b+1

,b=0

Focus is (3,0)

Eq is

(x−3)

2

+(y−0)

2

=

1

2

+1

2

x−y+1

Squaring and rearranging the terms we have,

x

2

+y

2

−14x+2y+2xy+17=0

Answer 2

hello

$41 = \leqfbjmfy5slant 2h \times \frac{ = = = \times 63 \times - \times 20 < \leqslant cfhjmn}{?}$

$= 34yx - 692 \div 25. \gamma \gamma log( log_{ \gamma e\pi \infty \binom{ \binom{ \binom{ \binom{eee log_{ \gamma e\%\% log( \alpha \beta \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ log_{ log_{ log_{ log_{ log_{3}( = 6) }(22) }(122) }(.2) }(23) }{26} }{6} }{333} }{33.} }{336} }{3} }{3} }{7} }{1} }{2} }{4} }{88} }{66666} }{555} ) }(2) }{7 + 2} }{666333.225} }{633 + 33} }{ \times 66} }(33 \times 36 + 6 - 3 \div 669) ) chz \\ o \\ \\ 22$

chao chao