Math, asked by linagouda22, 4 months ago

find factor of 3a+9b-6(a+3b)2​

Answers

Answered by Anonymous
1

Answer:

Factors of 2a+6b-3(a+3b)²=

(a+3b)(2-3a-9b)

Explanation:

Factorising 2a+6b-3(a+3b)²

= 2(a+3b)-3(a+3b)(a+3b)

= (a+3b)[2-3(a+3b)]

= (a+3b)(2-3a-9b)

Therefore,

2a+6b-3(a+3b)²

= (a+3b)(2-3a-9b)

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Answered by lunertrader
0

Answer:

same as above right just write more 3488722 .

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