Question

Find five Consecutive terms of an A.P. Such That sum of first three terms is 6 & sum of the remaining two terms is 14 .

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Answer 1

Answer:

Hey Sis I saw ur answer..u asked my name...it's given in my id...

well let me answer ur question...

Let the terms of AP be

A−2d,a−d,a,a+d,a+2d

A/Q

(a−2d)+(a−d)+a+a(a+d)+(a+2d)=60

5a=60⇒a=12

and a×(a+d)=172+a+2d

⇒a

2

+ad=172+a+2d

⇒144+12d=172+12+2d

⇒12d−2d=184−144=40

⇒10d=40⇒d=4

∴a=12,d=4

and the terms are

12−4×2,12−4,12,12+4,12+2×4

=4,8,12,16,20

Answer 2

Answer:

Hello didi..... mai upar wala answer ka malik hu...

iss hint se mujhe aap paichan lenge....

aapne mujse pucha tha ki mai kaisa hu....

Mai thik hu..... Waise "Hum fit toh india fit"

;)

:D

! D