Question

vii.
Pb has fcc structure with edge length
of unit cell 495 pm. Radius of Pb
atom is
a. 205 pm
c. 260 pm
b. 185 pm
d. 175 pm​

Answer 1

Answer:

c

Explanation:

c is correct ans .........

Answer 2

Explanation:

Answer: option d

given it is fcc,hence

4 r=1.41 a r=radius a=edge length

r= (1.41* 495)/4= 175 pm

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