Question

Find four consecutive terms in an



a.P whose sum is 88 and the sum of the first and the third terms is 40.

Answer 1

Let 4 numbers are a+3d, a+d,a-d,a-3d
4a= 88 ,a=22

a+2d+d=40
2a+2d=40
2*22+2d=40
d=-2
Answer= 22,20,18,16