Question

Find the coefficient of x^10 in binomial expansion 2x^2-x/2

Answer 1

x^2
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Answer 2

Answer:

Note that in the expansion of (x/2−4/x)6 the constant term is the fourth term which is C(6,3).(1/2)3.(−4)3=−160.

The term containing x2 is the fifth term which is C(6,4).(1/2)4.(−4)2=15.

Therefore, the coefficient of x2 in the expansion of (1+x2).(x/2−4/x)6 is given by −160+15=−145.