Math, asked by akashchauhanbhp, 1 year ago

find G.P 1,4,16,64
find the 9th term of GP 1, 4, 16, 64

Answers

Answered by mysticd
1
Hi ,

let a and r are first term and common

ratio of G. P

then the G.P is

a , ar , ar² ,....

n th term of G.P = an = ar^n-1

Here,

1 , 4 , 16 , 64 are in G. P

a = 1 ,

r = a2 / a1

r = 4/1 = 4

n = 9

a9 = 1 × 4^( 9 - 1 )

= 4^8

Therefore ,

9th term in G .P = 4^8

I hope this helps you.

:)

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