find general solution of 2cos x+√3=0
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Answered by
20
2cosx + √3 = 0
=> 2cosx = - √3
=> cosx = -√3/2
=> cosx = - cos30°
=> cosx = cos(180-30)
=> cosx = cos150°
=> x = 150
x = 180+30 = 210
so x = 150,210
=> 2cosx = - √3
=> cosx = -√3/2
=> cosx = - cos30°
=> cosx = cos(180-30)
=> cosx = cos150°
=> x = 150
x = 180+30 = 210
so x = 150,210
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Answered by
15
2 cos x + √3 = 0
Cos x = - √3 / 2
principal solutions: x = 180 - 30 = 150° or 180+30 = 210°
General solutions:
x = (2n+1) π + π/6 , n = an integer
x = 150°, 210°, 510, 570, ...
Cos x = - √3 / 2
principal solutions: x = 180 - 30 = 150° or 180+30 = 210°
General solutions:
x = (2n+1) π + π/6 , n = an integer
x = 150°, 210°, 510, 570, ...
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