Question

find gp whose 5th term is 48and eight teem is 384

Answer 1

Let the first term be 'a'

The common difference be 'r'

nth term is = a*r^(n-1)

So 

5th term is
48 = a*r^4    --------(1)    

8th term is
384 = a*r^7    --------(2)

do (1)/(2)
we get.
1/8 = 1/ r^3
r^3 = 8

which implies r = 2

Apply (3) in (1)

we get     

48 = a*2^4
a = 48/16
a=3

Therefore the GP is of the form

an = 3 * 2^(n - 1)