Question

find hcf and lcm of 11008 and 7344

Answer 1

Answer:

Step-by-step explanation:

11008 = 2^8 × 43

7344 = 2^4 × 7^2

Therefore, hcf = 2^4 = 16

Lcm = 2^8 × 43 × 7^2 = 539392

Answer 2

To find the LCM AND HCF OF 11008 and 7344 we have to find their prime factorization.

The  prime factorization of 11008 is

2|11008

2|5504

2|2752

2|1376

2|688

2|344

2|172

2|86

43|43

1

11008=2*2*2*2*2*2*2*2*43

11008=2^8*43

The prime factorization of 7344 is

2|7344

2|3672

2|1836

2|918

3|459

3|153

3|51

17|17

1

7344=2*2*2*2*3*3*3*17

7344=2^4*3^3*17

Now, HCF=Product of the smallest power of each common

prime factor in the numbers.

HCF=2^4=16

LCM = Product of the greatest power of each prime factor,

involved in the numbers.

LCM=2^8*43*3^3*17=256*43*27*17=5052672