Question

Find he value of k so that the following quadratic equation has equal roots:

2xsqare -(k-2)x+1=0

Answer 1

Answer:

Step-by-step explanation:

suppose the root of the equation is α and β;

α + β = (k-2)/2 and αβ = 1/2;

But the given condition say that α = β;

Now putting this

2α = (k-2)/2 and α²=1/2;

α = 1/√2; putting this value in 2α = (k-2)/2 we get

√2 = (k-2)/2;

2√2 + 2 = k

k = 2(1+√2)

Answer 2

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