Find if point (2k-3,k+2) lies on graph of equal 2x+3y+16=0.find value of k.
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(2k-3 , k +2) is lies on graph of equal 2x +3y +16 = 0
so,
2(2k -3) +3(k +2) + 16 = 0
4k -6 +3k +6 +16 = 0
7k = -16
k = -16/7
so,
2(2k -3) +3(k +2) + 16 = 0
4k -6 +3k +6 +16 = 0
7k = -16
k = -16/7
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