The interior angles of triangles are (3x-10), (3x+10), (3x).Find the angles
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3x-10+3x+10+3x=180
9x=180
x=20
9x=180
x=20
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The sum of all angles in a triangle =180
3x-10+3x+10+3x=180
9x=180
X=180/9
X=20
3x-10=3*20-10=60-10=50
3 X+10=70
3X=60
Hope it helped you
Mark as brainliest
3x-10+3x+10+3x=180
9x=180
X=180/9
X=20
3x-10=3*20-10=60-10=50
3 X+10=70
3X=60
Hope it helped you
Mark as brainliest
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