Find impossible blood groups in the following combination of parents 1. A x B 2. A x Heterozygous B 3. Heterozygous A x Heterozygous B 4. AB x AB 5. O x Heterozygous B 6. O x AB
Answers
Answer:
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Explanation:
A parent with A blood group can have two possible genotypes: “I
A
I
A
” and “I
A
I
O
”; similarly parent with B blood group can have two possible genotypes: “I
B
I
B
” and “I
B
I
O
”. If both the parents are homozygous (I
A
I
A
x I
B
I
B
) , all of their children will have AB blood group. But if father is heterozygous (I
A
I
O
”) and mother is homozygous (I
B
I
B
); the total different types of possible combinations by three alleles (I
A
, I
B
and I
O
) will be (I
A
I
B
and I
B
I
O
). But if mother is heterozygous (I
B
I
O
) and father is homozygous (I
A
I
A
); the total different types of possible combinations by three alleles (I
A
, I
B
and I
O
) will be (I
A
I
B
and I
B
I
O
).
Cross 1
Parent generation : I
A
I
A
x (I
B
I
B
)
Gametes :
I
A
I
A
-->
(I
A
I
B
)
I
A
I
A
I
B
I
A
I
B
I
A
I
B
I
B
I
A
I
B
I
A
I
B
F
1
generation phenotypic ratio = All AB group
Cross 2
Parent generation: I
A
I
O
X (I
B
I
B
)
Gametes
I
A
I
O
-->
I
B
I
B
I
A
I
O
I
B
I
A
I
B
I
B
I
O
I
B
I
A
I
B
I
B
I
O
F
1
generation phenotypic ratio = 1 AB group : 1 B group
Cross 3
Parent generation: I
A
I
A
X (I
B
I
O
)
Gametes
I
A
I
A
-->
I
B
I
B
I
A
I
A
I
B
I
A
I
B
I
A
I
B
I
O
I
A
I
O
I
A
I
O
F
1
generation phenotypic ratio = 1 AB group : 1 A group
Cross 4
Parent generation: I
A
I
O
X (I
B
I
O
)
Gametes :
I
A
I
O
-->
I
B
I
O
I
A
I
O
I
B
I
A
I
B
I
B
I
O
I
O
I
A
I
O
I
O
I
O
F
1
generation phenotypic ratio = 1 AB