Math, asked by MeSrijal, 1 year ago

Find k for the following equation to have real and equal roots.

k {x}^{2}  + 4x + 1 = 0
Pls explain.

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Answers

Answered by prachi7255
1

If the roots are real and equal

b^2 -4ac>0

let a=k,b=4,c=1

b^2-4ac=0

4^2-4kx1=0

16-4k=0

-4k=-16

k=4

hope it help


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