Question

Find largest no. which exactly divides280 and 1245 leaving remainders 4 and 3 respectively

Answer 1

hi

aim :  Find largest no. which exactly divides280 and 1245 leaving remainders 4 and 3 respectively

280 - 4 = 276

1245 - 3 = 1242

now let us find the hcf of 276 and 1242

276 =  2 x 2 x 3 x 23

1242 =  2 x 3 x 3 x 3 x 23

now  hcf = 2× 3×23

= 138


hence 138 is  the  largest no. which exactly divides280 and 1245 leaving remainders 4 and 3 respectively

hope it helps u

:)

Answer 2

Heya !!!!



280 - 4 = 276


1245 -3 = 1242



Prime factorisation of 276 = 2 × 2 × 3 × 23


Prime factorisation of 1242 = 2 × 3 × 3 × 3 × 23



Required Number = HCF of 276 and 1242 = 2 × 3 × 23 = 138.



Hence,


138 is a largest Number that Divides 280 and 1245 leaves Remainder 4 and 3 is 138.



HOPE IT WILL HELP YOU...... :-)