Question

find LCM and hcf of 306 and 657 .verify that lcm x hcf= product of two numbers

Answer 1

Answer:

Step-by-step explanation:

Prime factorisation of 306 = 2×3×3×17

Prime factotisation of 657 =3×3×73

so , HCF = 3×3 = 9

LCM = 2×3×3×17×73 = 22338

We knoew that

HCF × LCM = prod. of two no

9×22338 = 306×657

201,042= 201,042

Hence verified

Answer 2

Given,

a = 306

b = 657

To Find,

LCM and HCF of a and b, and hence verify lcm x hcf = product of two numbers

Solution,

The given numbers are 306 and 657

The LCM and HCF of these numbers can be found out using the method of prime factorization

The prime factorization of 306 and 657 are:

306 = 2 × 3² × 17

657 = 3² × 73

Now, HCF of these numbers are given by multiplying the common factors of these numbers

The common factors of 306 and 657 is 3²

Therefore, HCF = 3² = 9

Now, the LCM is given by multiplying the HCF of 306 and 657 with the non-common prime factors of 306 and 657

Therefore, LCM = 9 × 2 × 17 × 73 = 22,338

Now, LCM × HCF = 9 × 22,338 = 201042

a × b = 306 × 657 = 201042

Hence verified that LCM × HCF = product of the two numbers

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