Question

Find maximum height of a projectile using conservation of energy.

Answer 1

Answer:

ball is launched as a projectile with initial speed v at an angle θ above the horizontal. Using conservation of energy, find the maximum height hmax of the ball's flight. Express your answer in terms of v, g, and θ.

I am doing:

12mv2v2hmaxhmaxhmax=mghmax+12m(vcosθ)2=2ghmax+(vcosθ)2=(v2−(vcosθ)2)/2g=v2(1−(cosθ)2)/2g=v2sin2θ2g