Question

Find minimum velocity of water at which it crosses the wall

Answer 1

Explanation:

helloo

It's an example of ground to ground projectile

we know formula=>

$h = \frac{ {u}^{2} { \sin(theta) }^{2} }{2g} \\ 80 = \frac{ {u}^{2} { \sin(32) }^{2} }{20} \\ 1600 = \frac{ {u}^{2} \times 0.2808 }{1} \\ {u}^{2} = 5698 \\ u = 75.48 \\ \\ hope \: it \: helps \: uh..$