Question

find no of gold atims ina coin with diameter of 1cm and thickness of 1 mm​

Answer 1

Explanation:

#rho, "density"="mass"/"volume"#

And thus #"mass"# #=# #rhoxx"volume"#, and we know the #"volume"# of a cylinder is #pixxr^2xxl#, where #r="diameter"/2#, and #"length"# is as given.

And thus #"mass"=19.3*g*cm^-3xxpixx0.300*cmxx(1.10*cm)^2=??g#