Question

Find number of moles in 87 g of K2SO4

Answer 1

molecular mass of K2SO4 = 39*2+32+16*4 = 78+32+64= 174g
174 g of K2SO4 contains = 1 mole
87 g of K2SO4 contains = 87 / 174 2 = 0.5 moles ANS...

Answer 2

Answer:

Formula weight of K2SO4 (Molar Mass in grams):

=2(39)+(32)+4(16)

=78+32+64

=174g

Given Mass of K2SO4=87g

Number of moles=Given mass/Molar Mass

So, n=87/174

=1/2=0.5mol.

Therefore, There are 0.5 mol. of Potassium Sulphate present in 87g of it