Find out how many distinct three-digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 such that the digits are in ascending order.
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Given:
Digits = 1, 2, 3, 4, 5, 6, 7, 8, 9
To find:
3 digit numbers that can be formed using these digits such that the digits are in ascending order.
Solution:
Number of ways to choose 3 digits from 9 numbers without repetition:
= ⁹C₃ = 84
There would only be a single way in which the digits are arranged in ascending order.
For example if we have selected 3 digits: 8, 5, 3
Then there is only one way to arrange them in ascending order, and the number is 853.
Therefore 84 numbers can be formed.
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