Question

Find out t1/2 and t3/4between relation in first order reaction

Answer 1

first order reaction

 K x t = 2.303 log(a/a-x)
 K x t1/2 = 2.303 log{a/(a-a/2)}
t1/2 =0.693 /K----------(1)

and K x t3/4 =2.303 log{a/(a-a/4)}
       t3/4 = 2 (0.693 /K)-------(2)

t3/4 = 2(t1/2)


regards