Find out t1/2 and t3/4between relation in first order reaction
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first order reaction
K x t = 2.303 log(a/a-x)
K x t1/2 = 2.303 log{a/(a-a/2)}
t1/2 =0.693 /K----------(1)
and K x t3/4 =2.303 log{a/(a-a/4)}
t3/4 = 2 (0.693 /K)-------(2)
t3/4 = 2(t1/2)
regards
K x t = 2.303 log(a/a-x)
K x t1/2 = 2.303 log{a/(a-a/2)}
t1/2 =0.693 /K----------(1)
and K x t3/4 =2.303 log{a/(a-a/4)}
t3/4 = 2 (0.693 /K)-------(2)
t3/4 = 2(t1/2)
regards
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