Question

find out the integration of (x+1)​

Answer 1

integral of x+1

$= > \frac{ {x}^{2} }{2} + x + c$

where c is integral constant

Answer 2

We need to find the integral of x+1.

For that we need to remember 3 rules in this case.

$\int{x+a} \, dx =\int{a} \, dx+\int{x} \, dx$

$\int{x^n} \, dx = \frac{x^{n+1}}{n+1}+c$

$\int{a} \, dx = ax+c$

Now let us apply integral here.

$\int({x+1} )\, dx =\int{1} \, dx+\int{x} \, dx$

                   $=x+\frac{x^2}{2}+c$

                 

Please note that c is integral constant used in indefinite integration.