find out the number of constituent atoms present in 49g of H2SO4
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Molar mass of h2so4-
H-2
S-32
O-16
So total=1*2+1*32+4*16=98gm
So in 49gm half moles of h2so4 is present
I.e. 6.022*10raise to the power 23*1/2 molecules of h2so4 -(1)
Now one molecule contai 7atoms so
Total atoms are 7*(1)
Hope it helps
H-2
S-32
O-16
So total=1*2+1*32+4*16=98gm
So in 49gm half moles of h2so4 is present
I.e. 6.022*10raise to the power 23*1/2 molecules of h2so4 -(1)
Now one molecule contai 7atoms so
Total atoms are 7*(1)
Hope it helps
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