Question

Find out the resulting normality
(1) 0.4 M Ca(OH)2(50ml)+0.4N Naoh(30 ml) + 0.04M Koh(10 ml)​

Answer 1

Answer:

0.11N

Explanation:

2×0.4×250 + 0.4×30 + 0.04×10 = N(250 + 30 +10)

or, 290 N = 32.4

or, N = 32.4/290= 0.11N