Question

Find Oxidation number of underlined element
in the following:
​

Answer 1

Answer:

HN03 =

let oxidation number if N be x

1 + x + (-2)×3 = 0

1 + x - 6 = 0

x -5 = 0

x = +5

Cr2O7 =

let oxidation number if Cr be x

2x + (-2)× 7 = 0

2x = 14

x = +7

bt it is not possible

so Cr oxidation state is +6

Answer 2

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