Question

Find p(0) and p(-1) of p(t) =t^2 + t-5​

Answer 1

Answer:

p(t)=t^2+t-5

p(0)=0^2+0-5

p(0)=-5

p(-1)=(-1)^2+(-1)-5

p(-1)=1+(-6)

p(-1)=-5

p(0)=-5

p(-1)=-5