Question

Find p(0)and p(1) when p(x) = x2+3x-2
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

p(0)= -2 and p(1) = 2

Step-by-step explanation:

p(x) = x²+3x-2

p(0) = (0)²+3(0)-2

= 0+0-2

=-2

p(1) = (1)²+3(1)-2

= 1+3-2=4-2

= 2

hope it helps...